Class 1013

1013

Run Multiple Choice Generator at h:\shares\physics

Run Core Problems by giving the program qzz as your 'course'--enter this when asked for your 3-digit course number. Do the Physics Quiz 1013.
If you miss a problem be sure to click on Comment and explain what you do and do not understand about the question and the given solution.

yes	n	The net force acting on a particle is the sum of all the forces you happen to think of. && Please let this answer be an error. &&
no	n	If identical net forces act on two particles, one with greater mass than the other, the rate of change of velocity will be greater for the more massive particle. && The same force on a greater mass results in less acceleration. &&
no	n	If identical net forces act on two particles, one with greater mass than the other, the rate of change of velocity will be greater for the more massive particle.
yes	n	The average rate of change of A with respect to B is A / B && change in A / change in B, not A / B. &&
yes	n	If identical net forces act on two particles, one with greater mass than the other, the rate of change of velocity will be the same for both. && greater mass, same force implies less accel &&
yes	n	If identical net forces act on two particles, one with greater mass than the other, the rate of change of velocity will be the same for both.
no	n	If identical net forces act on two particles, one with greater mass than the other, the rate of change of velocity will be the same for both.
yes	n	slope represents average acceleration because rise represents change in position, run represents change in clock time so slope represents change in position * change in clock time, which is the average rate of change of position with respect to clock time, which is average velocity
no	n	The net force acting on a particle is the sum of all forces acting in the general vicinity.
yes	n	The net force acting on a particle is the sum of all forces acting in the general vicinity.
yes	n	If identical net forces act on two particles, one with greater mass than the other, the rate of change of velocity will be the same for both.
yes	n	If you push a car uphill you are storing energy in the system consisting of car and hill. When you release the car most of the stored energy is converted to energy of motion. The stored energy in this case is elastic.
yes	n	It takes less than 2.46 seconds to roll the first half of the distance.
yes	n	If identical net forces act on two particles, one with greater mass than the other, the rate of change of velocity might be greater or might be less for the more massive particle, depending on the mood of the evil spirit that inhabits it.
no	n	for a trapezoid on a graph of position vs. clock time t slope represents average acceleration because rise represents average velocity, run represents change in clock time so slope represents average velocity / change in clock time, which is the average rate of change of velocity with respect to clock time, which is average acceleration && rise on a position vs. clock time trapezoid represents change in position, not change in velocity. &&
yes	n	If identical net forces act on two particles, one with greater mass than the other, the rate of change of velocity might be greater or might be less for the more massive particle, depending on the mood of the evil spirit that inhabits it. && That 'yes' answer must be a typo. &&
yes	n	If identical net forces act on two particles, one with greater mass than the other, the rate of change of velocity might be greater or might be less for the more massive particle, depending on the mood of the evil spirit that inhabits it.
yes	n	If identical net forces act on two particles, one with greater mass than the other, the rate of change of velocity might be greater or might be less for the more massive particle, depending on the mood of the evil spirit that inhabits it.
yes	n	If the period of a pendulum is .500 seconds and an observation of this period is in error by .0700 seconds, then The error is 14.0 of the period. && The error is 14.0 % of the period, not 14.0 of the period. .07 / .50 = .14 or 14%. &&
yes	n	The error is .140 % of the period. && The error is 14% of the period. &&
yes	n	What happens to the period and/or frequency of the pendulum if you double its length? The period decreases but to less than half. && the period increases to less than twice as much &&
no	n	If the net force acting on a particle is not zero then the particle will change its speed. && This is a true statement &&
no	n	If identical net forces act on two particles, the rates of change of velocity will have magnitudes which are inversely proportional to the squares of their masses. && a = F / m, not a = F / m^2, so acceleration is inversely proportional to the first power of the mass. &&
yes	n	If identical net forces act on two particles, the rates of change of velocity will have magnitudes which are inversely proportional to the squares of their masses.
no	n	If identical net forces act on two particles, the rates of change of velocity will have magnitudes which are inversely proportional to the squares of their masses.
yes	n	If the period of a pendulum is .500 seconds and an observation of this period is in error by .0700 seconds, then The proportional error is 14.0 . && The proportional error is .14 && .
yes	n	If the net force acting on a particle is not zero then the particle will change its direction. && Might just change speed and not direction. &&
yes	n	If identical net forces act on two particles, the rates of change of velocity will have magnitudes which are inversely proportional to the square roots of their masses. && ... inv prop to mass &&
yes	n	If the net force acting on a particle is not zero then the particle will change its direction.
yes	n	If identical net forces act on two particles, the rates of change of velocity will have magnitudes which are inversely proportional to the square roots of their masses.
no	n	If identical net forces act on two particles, the rates of change of velocity will have magnitudes which are inversely proportional to the square roots of their masses.
no	n	If the period of a pendulum is .500 seconds and an observation of this period is in error by .0700 seconds, then The percent error is .140 . && percent error is 14%. &&
no	n	If identical net forces act on two particles, the rates of change of velocity will have magnitudes which are directly proportional to their masses. && accel is inversely prop to mass; a = Fnet / m &&
no	n	If identical net forces act on two particles, the rates of change of velocity will have magnitudes which are directly proportional to their masses.
no	n	If identical net forces act on two particles, the rates of change of velocity will have magnitudes which are directly proportional to their masses.
yes	n	If the net force acting on a particle is not zero then it is possible that the particle's speed and direction will remain unchanged.
yes	n	If the net force acting on a particle is not zero then it is possible that the particle's speed and direction will remain unchanged. && a = Fnet / m; if Fnet isn't zero then a isn't 0 and the change in velocity over any finite time interval won't be zero (i.e., `dv = a `dt won't be zero). &&
yes	n	If identical net forces act on two particles, the rates of change of velocity will have magnitudes which are directly proportional to their masses.
yes	n	If identical net forces act on two particles, the rates of change of velocity will have magnitudes which are directly proportional to their masses.
yes	n	When you push a pendulum away from its equilibrium position you are storing energy in the pendulum, and if you release the pendulum the stored energy is gradually changed to energy of motion. As the pendulum swings past equilibrium its energy of motion begins to decrease and it begins to store energy again, reaching maximum stored energy at the instant it stops and begins swinging back toward equilibrium. The stored energy in this case is elastic. && Everything is right until that last statement. The stored energy isn't elastic. The stored energy results from the higher position of the pendulum, and is gravitational in nature. &&
yes	n	When you push a pendulum away from its equilibrium position you are storing energy in the pendulum, and if you release the pendulum the stored energy is gradually changed to energy of motion. As the pendulum swings past equilibrium its energy of motion begins to decrease and it begins to store energy again, reaching maximum stored energy at the instant it stops and begins swinging back toward equilibrium. The stored energy in this case is elastic.
yes	n	Average velocity * change in clock time = change in acceleration.. && ave vel is rate of change of position with respect to clock time so Average velocity * change in clock time = change in position. &&
no	n	The average rate of change of A with respect to B is (B2 - B1) / (A2 - A1), where A1 and A2 are the two values of A that occur when B takes respsective values B1 and B2. && change in A / change in B, not change in B / change in A &&
yes	n	If a particle changes its speed, its direction or both, the net force acting on the particle might or might not be zero. && velocity is speed and direction. If speed, direction or both change then velocity changes. If velocity changes then acceleration is not zero. If accel is not zero then net force = m * a is not zero. &&

Click here for Part 2 of today's notes: Part 2.