PHY 121
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
answer/question/discussion: ->->->->->->->->->->->-> :
2 s / 3 = .7s to get from one extreme point to equilibrium. So to get from one extreme point to the other you would double this. Therefore, it would 1.4 s to get from one extreme point to the other.
It would take 2s.
• What reasonable assumption did you make to arrive at your answers?
answer/question/discussion: ->->->->->->->->->->->-> :
Well if it takes the pendulum 2 s to complete a cycle ( extreme point to equilibrium to extreme point back to equilibrium) you can divide this into 3rds. When you do that it takes .7 s for the pendulum to go from one extreme point to the equilibrium. Then all you have to do is count how many times it covers this distance.
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20 minutes
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Solution
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