PHY 121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
F = m * a
F = 12 kg * 3 m/s^2
F = 36 Newtons
• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
a = F / m
a = 20 newtons / 4 kg
a = 5 m/s^2
• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
Because if there were no other forces acting on the object, then it would be accelerating at a rate o 2 m/s^2. However, since the object is only accelerating at 1.5 m/s^2 , there is a difference of .5 m/s^2 which means you are having to overcome some other force inorder to get the object to move.
• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
20 Newtons + 5 Newtons = 25 Newtons
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See the link for more discussion, especially regarding the last question:
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#
PHY 121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
F = m * a
F = 12 kg * 3 m/s^2
F = 36 Newtons
• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
a = F / m
a = 20 newtons / 4 kg
a = 5 m/s^2
• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
Because if there were no other forces acting on the object, then it would be accelerating at a rate o 2 m/s^2. However, since the object is only accelerating at 1.5 m/s^2 , there is a difference of .5 m/s^2 which means you are having to overcome some other force inorder to get the object to move.
• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
20 Newtons + 5 Newtons = 25 Newtons
** **
** **
Good, but see the link regarding that last question.
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#