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A child in a car tosses a ball upward so that after release it requires 1/2 second to rise and fall back into the child's hand at the same height from which it was released. The car is traveling at a constant speed of 10 meters / second in the horizontal direction.
• Between release and catch, how far did the ball travel in the horizontal direction?
answer/question/discussion: ->->->->->->->->->->->-> :
(10 m/s)/.5 s= 10 meters
• As observed by a passenger in the car, what was the path of the ball from its release until the instant it was caught?
answer/question/discussion: ->->->->->->->->->->->-> :
If a passenger in another car was observing the ball it would look like the ball was going in a fairly straight line, when it is thrown up and then caught.
• Sketch the path of the ball as observed by a line of people standing along the side of the road. Describe your sketch. What was shape of the path of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
My sketch showed the ball going up and moving towards the kid, and then moving back down. The shape of the path was a curve.
• How fast was the ball moving in the vertical direction at the instant of release? At that instant, what is its velocity as observed by a line of people standing along the side of the road?
answer/question/discussion: ->->->->->->->->->->->-> :
The ball is moving in the vertical direction 10 m/s. I’m not sure how to find the velocity with only those two numbers.
• How high did the ball rise above its point of release before it began to fall back down?
answer/question/discussion: ->->->->->->->->->->->-> :
It would approximately rise about ½ meter.
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30 minutes
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Good answers on most questions. However your numbers on the vertical motion aren't quite correct. See the link:
&#Please compare your solutions with the expanded discussion at the link
Solution
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