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Phy 201
Your 'cq_1_01.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
Here is the definition of rate of change of one quantity with respect to another:
The average rate of change of A with respect to B on an interval is
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average rate of change of A with respect to B = (change in A) / (change in B)
Apply the above definition of average rate of change of A with respect to B to each of the following. Be sure to identify the quantity A, the quantity B and the requested average rate.
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If the position of a ball rolling along a track changes from 10 cm to 20 cm while the clock time changes from 4 seconds to 9 seconds, what is the average rate of change of its position with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> n/discussion (start in the next line):
The change in A would be 10 cm (10 to 20) and the change in B would be 5 seconds ( 4 to 9 seconds). The average rate of change would be 10 cm/5 seconds or 2 cm/sec.
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If the velocity of a ball rolling along a track changes from 10 cm / second to 40 cm / second during an interval during which the clock time changes by 3 seconds, then what is the average rate of change of its velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
If the change in cm is 30 cm (10 to 40 cm) and the change in seconds is 3 seconds then the formula is 30 cm/3 seconds. The average rate of change would be 10 cm/second.
10 cm and 40 cm are not quantities relevant to this question.
10 cm/s and 40 cm/s are, but they are very different from 10 cm and 40 cm.
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If the average rate at which position changes with respect to clock time is 5 cm / second, and if the clock time changes by 10 seconds, by how much does the position change?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
The change in position would be 50 cm because 50 cm/10 seconds would equal 5 cm/sec.
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You will be expected hereafter to know and apply, in a variety of contexts, the definition given in this question. You need to know this definition word for word. If you try to apply the definition without using all the words it is going to cost you time and it will very likely diminish your performance. Briefly explain how you will ensure that you remember this definition.
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
I have added this definition to my notes to ensure I review it often.
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You are asked in this exercise to apply the definition, and given a general procedure for doing so. Briefly outline the procedure for applying this definition, and briefly explain how you will remember to apply this procedure.
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
I have applied this definition by learning the definition and then using it in a variety of different word problems to ensure my understanding. I will remember this because I have added it to my notes, have saved this document and I was able to practice it in a few different ways.
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I spent approx. 8 minutes on this question.
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&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#
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