Phy 201
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
answer/question/discussion: ->->->->->->->->->->->-> : It takes 2 seconds to get from one extreme point to the other, 1 second to get from one extreme to the equilibrium, and 2.5 seconds to go from one extreme to the other extreme and then back to equilibrium.
• What reasonable assumption did you make to arrive at your answers?
answer/question/discussion: ->->->->->->->->->->->-> : The only reasoning I based my answer off was the fact that it takes 2 seconds for the pendulum to get from one extreme to the other. Then all other answers were based that it equally took the same amount of time to move from equilibrium to the extreme.
From one extreme to another is only half a cycle. To complete a cycle the pendulum has to come back to its original point, moving at its original velocity (in this case zero).
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About 20 minutes...
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Solution
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