Phy 201
Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Sketch a vector representing a 10 Newton force which acts vertically downward.
• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> : Did this
• What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> : I thought to find equilibrant we needed two points. I am unsure how to answer this. Could we assume that 10N is the length of L and then find cos(theta)(L and sin(theta)(L) to find the lengths and therefore points of the vector. Would this be an equilibrant force?
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15 mins
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You're on the right track. Theta would be the angle from the positive x axis to the equilibrant, measured counterclockwise. The equilibrant is equal and opposite to the original force--i.e., it's a vector of equal length, directed at 180 degrees from the original.
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#