Phy 201
Your 'cq_1_01.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
Here is the definition of rate of change of one quantity with respect to another:
The average rate of change of A with respect to B on an interval is
average rate of change of A with respect to B = (change in A) / (change in B)
Apply the above definition of average rate of change of A with respect to B to each of the following. Be sure to identify the quantity A, the quantity B and the requested average rate.
If the position of a ball rolling along a track changes from 10 cm to 20 cm while the clock time changes from 4 seconds to 9 seconds, what is the average rate of change of its position with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Quantity A is the position and quantity B is the clock time. The average rate of change of A with respect to B = (change in A) / (Change in B).
= (20-10) / (9-4)
=10cm / 5 seconds
=2 cm/sec
The average rate of change of its position with respect to clock time during this interval is 2 cm per second.
#$&*
If the velocity of a ball rolling along a track changes from 10 cm / second to 40 cm / second during an interval during which the clock time changes by 3 seconds, then what is the average rate of change of its velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Quantity A is the position and quantity B is the clock time. The average rate of change of A with respect to B = (change in A) / (Change in B).
(40cm/s 10cm/s) / (3s-0s)
(30cm/s) / 3s
10 cm/s
The average rate of change of its position with respect to clock time during this interval is 10 cm per second
Your units aren't completely correct here. Be sure to check the discussion in the link given at the end of this document.
#$&*
If the average rate at which position changes with respect to clock time is 5 cm / second, and if the clock time changes by 10 seconds, by how much does the position change?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Quantity A is the position and quantity B is the clock time. We are solving for the position change (A). We know what the average rate is.
Average rate = (change in A) / (Change in B)
5cm/s = (x) / (10s- 0s)
5cm/s = (x) / (10s)
Multiply 10s by 5 cm/s to find x
X= 50 cm
The position changes 50 cm.
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You will be expected hereafter to know and apply, in a variety of contexts, the definition given in this question. You need to know this definition word for word. If you try to apply the definition without using all the words it is going to cost you time and it will very likely diminish your performance. Briefly explain how you will ensure that you remember this definition.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
I will make sure to look over the definition so that I have it memorized and know it. Im going to write it on a note card so its easy to have and study.
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You are asked in this exercise to apply the definition, and given a general procedure for doing so. Briefly outline the procedure for applying this definition, and briefly explain how you will remember to apply this procedure.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The definition is the average rate of change of A with respect to B = (Change in A) / (Change in B). In order to apply this definition you have take the change in position divided by the change in time it took for the procedure to happen. I will remember to apply this procedure whenever I see a question asking what the average rate is.
#$&*
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45 minutes
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&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
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