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Phy 201
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
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How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
1 second
.5 second
1.5 second
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answer/question/discussion: ->->->->->->->->->->->-> scussion:
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What reasonable assumption did you make to arrive at your answers?
One full cycle is 2 seconds, which is from first extreme point to other extreme point, back to original position.
Extreme point to the other is half a cycle, therefore 1 second.
Extreme point to equilibrium is one quarter a cycle, therefore a half second.
Extreme point to equilibrium to opposite extreme point and back to equilibrium is 3/4 cycles, therefore 1.5 seconds.
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answer/question/discussion: ->->->->->->->->->->->-> scussion:
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20 minutes
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9/30 2 am
&#Very good responses. Let me know if you have questions. &#
&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#