Phy 201
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
F = m * a
= 12kg * 3m/s^2
=26N
36 N; likely typo since your previous step was correct
#$&*
• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
a = F / m
=20N / 4 kg
= 5m/s^2
#$&*
• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
a = 20N / 10 kg
a = 2 m/s^2
Since a = 1.5m/s^2 you know there is some force acting .5m/s^2
#$&*
• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
The total of all the forces is 1.5m/s^2 in the direction of motion and .5m/s^2 in the opposite of the direction of motion.
#$&*
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10 min
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Good, but check out the discussion of the last two questions. You'll understand.
&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#