Phy231
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Seed 10.1
A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point
to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the
amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared
to the length of the pendulum, the time required for a cycle is independent of the amplitude.
How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how
long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
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answer/question/discussion: ->->->->->->->->->->->-> :
What reasonable assumption did you make to arrive at your answers?
I'm not sure how to answer this question without any numbers. I would guess it would take the same amount of time to
get from one extreme point to another. I would also imagine that the cycles would be very short with such a short pendulum,
the shorter the pendulum the quicker the cycles.
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answer/question/discussion: ->->->->->->->->->->->-> :
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10min
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3/28/10 5:30pm
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#