PHY 121
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A ball rolls off the end of an incline with a vertical velocity of 20 cm/s downward, and a horizontal velocity of 80 cm/s. The ball falls freely to the floor 120 cm below.
• For the interval between the end of the ramp and the floor, hat are the ball's initial velocity, displacement and acceleration in the vertical direction?
80cm/s – 20cm/s = 60cm/s
120cm / 60cm/s = 2cm/s^2
What therefore are its final velocity, displacement, change in velocity and average velocity in the vertical direction?
2cm/s^2 * 2 =4cm/s^2
60cm/s / 4cm/s^2 =15cm/s
• What are the ball's acceleration and initial velocity in the horizontal direction, and what is the change in clock time, during this interval?
80cm/s – 20cm/s = 60cm/s
??
• What therefore are its displacement, final velocity, average velocity and change in velocity in the horizontal direction during this interval?
??
• After the instant of impact with the floor, can we expect that the ball will be uniformly accelerated?
yes
• Why does this analysis stop at the instant of impact with the floor?
Because the ball stops
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20 min
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Please compare your solutions with the expanded discussion at the link
Solution
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