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Phy 231
Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Sketch a vector representing a 10 Newton force which acts
vertically downward.
Position an x-y coordinate plane so that the initial point of
your vector is at the origin, and the angle of the vector as
measured counterclockwise from the positive x axis is 250
degrees. This will require that you 'rotate' the x-y coordinate
plane from its traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> :
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What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> :
x = 10 cos(250) = -3.42
y = 10 sin(250) = -9.40
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*#&!
@& Those are the x and y components of the force. The equilibrant is equal and opposite to the force.*@
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See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem.
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