PHY 231
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
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answer/question/discussion: ->->->->->->->->->->->-> :
It would take one second to go from one extreme point to another. From an extreme point to equilibrium would take half a second. From extreme to extreme to equilibrium would be 1.5 seconds.
What reasonable assumption did you make to arrive at your answers?
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answer/question/discussion: ->->->->->->->->->->->-> :
Since a complete back and forth cycle takes 2 seconds, it is safe to assume the average time for a half a cycle is half the time, one second. Half of a half of a cycle (quarter cycle) is from extreme to equilibrium. This takes half the time as before, thus it would take a half a second. To go from extreme to equilibrium to extreme to equilibrium is 3/4 of a cycle thus taking 3/4 of the 2 second period which is a second and a half.
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5 minutes
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Solution
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