phy201
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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seed 10.1
A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
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answer/question/discussion: ->->->->->->->->->->->-> :
To go from extreme point to equiibrium is one positions
to go from equilibrium to extreme point is two postions
and to go from that extreme point to equilibrium is three positions
and to from equilibrium to back to the origianl postion would be the 4 position with respect to the two second complete cycle
so, I would think that each position takes aboat .5 of a second.
I would think to go from extreme point to the net extreme point would be 1 second.
To go from an extreme point to equilibrium would take .5 of a second
To go from extreme point to equilibrium (1) to opposite extreme point and back to equilibrium(2) would take one second.
What reasonable assumption did you make to arrive at your answers?
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answer/question/discussion: ->->->->->->->->->->->-> :
I assumed that there were four total postions and I divided the given clocktime by those four positions to get approximately half of a second per each postion. And then to answer each question I added up the postions to get the time.
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About 15 minutes
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Solution
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