phy201
Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Sketch a vector representing a 10 Newton force which acts vertically downward.
Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured
counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its
traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> :
90- 250= 160deg
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What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> :
x= 10 cos(160deg) = -9.39
y= 10 sin(160deg) = 3.42
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I am having trouble with these questions
You don't need to subtract 90 degrees. The original coordinate system, with the downward vertical vector at 270 degrees, has to rotate only 20 degrees to make the angle 250 deg. Check the link. You should submit the revision on this one, just to be sure you understand (and to answer questions if you don't).
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#