Set 1 Problem number 6


Problem

Problem:  How long does it take an object moving at 5 meters/second to move 4.5 meters?

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

Solution

Solution: At 5 meters every second, it will clearly take less than a second to move 4.5 meters. The ratio of distance moved to distance in a second is 4.5 / 5, so the time interval is 4.5 / 5 seconds = .9000 second.

Generalized Solution

Generalized Response: We can obviously rearrange

`dist = v `dt

into the form

`dt = `dist / v.

This form represents the ratio `dist / v of the distance moved to the distance moved in a second.

If, as in the present problem, the numerical value of `dist is less than that of v, this means that we have moved less distance than would be moved in a second. So the time interval `dt is less than a second.

The smaller the ratio `dist / v, the less the time required.

.

.

.

.

.

.

.

.

.

.

Explanation in terms of Figure(s), Extension

Figure description:

We can reason out the result, as above. As an alternative, the figure below shows the diagram in the form of a 'relationship triangle' between `ds, `dt and vAve, showing how we can use the known quantities `ds and vAve to find the time interval `dt.

Figure(s)

the_v_ds_dt_triangle.gif (3046 bytes)