Problem: An object moves both horizontally and vertically. Its horizontal motion is at a constant velocity of 72.4 m/s; its vertical motion begins at velocity zero and it accelerates in that direction at a constant rate of 9.8 m/s/s. How far does it travel horizontally, and how far vertically, in .7400 seconds?
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Solution: The motion of this object is equivalent to the motion of two objects, one moving horizontally and one vertically, with the specified distances, speeds and accelerations. So imagine the two objects. In .7400 seconds the first object, traveling at 72.4 m/s, will travel ( 72.4 m/s)( .7400 sec) = 53.57 meters. The second object will attain a speed of (9.8 m/s/s)( .7400 sec) = 7.252 m/s; its average speed will be (0+ 7.252 m/s)/2 = 3.626 m/s, and the distance will be ( 3.626 m/s)( .7400 sec) = 2.683 m.
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