Problem: An object falls freely from rest in the vicinity of the earth's surface. .3000 seconds seconds later, how fast will it be moving and how far will it have fallen?
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Solution: In the vicinity of the Earth's surface, an object will accelerate at 9.8 m/s/s. In .3000 seconds, an object accelerating from rest at 9.8 m/s/s will attain a speed of 2.94 m/s. Its average speed will be (0+ 2.94)/2 m/s = 1.47 m/s. Thus in .3000 seconds its speed will be ( 1.47 m/s)( .3000 sec) = .4410 m/s.
Generalized Response:
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Figure description: