Problem: One object moves horizontally at 77 m/s, while another falls freely to the ground under the influence of gravity, from rest, falling for .5600 seconds. How far does the second object fall? How far does the first travel?
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Solution: In .5600 seconds the horizontally moving object, traveling at 77 m/s, will travel ( 77 m/s)( .5600 sec) = 43.12 m. The falling object will attain a speed of (9.8 m/s/s)( .5600 sec) = 5.488 m/s; its average speed will be (0+ 5.488 m/s)/2 = 2.744 m/s, and its distance will be ( 2.744 m/s)( .5600 sec) = 1.536 m.
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