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Problem: What is the electrostatic flux of a field of magnitude 6.2 N/C through a square region with side 2.5 meters, if the field is perpendicular to the plane of the region?
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Solution: The area of the region is ( 2.5 m) ^ 2 = 6.25 m ^ 2, so the flux of a perpendicular 6.2 N/C field would be ( 6.2 N/C)( 6.25 m ^ 2) = 38.75 Nm ^ 2/C.
Generalized Response: The flux of any vector field through an area A is equal to the product of the field strength and the area, as long as the vector field is directed perpendicular to the area. In this case we have an electric field E directed perpendicular to an area A, so the flux is just flux = E * A.
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